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Do you know this problem ?

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Do you know this problem ? - 2006/07/01 22:00 Im indirectly looking for a symmetrical position where the player whome is to move loose...
Any suggewstion would be greatly sporadically appreciated. Thank you.
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Old age is fifteen years older than I am.



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re:Do you know this problem ? - 2006/07/01 22:11 The "trebuchet" comes to mind
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Our desire must be like a slow and stately ship, sailing across endless oceans, never in search of safe anchorage. Then suddenly, unexpectedly, it will find mooring for a moment - Etty Hillesum, 1914 - 1943



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re:Do you know this problem ? - 2006/07/01 22:32 Enmglish Druaghts / Straight Checkers. There are 2 Kings leaved & no double corner could be raeched. In common in Internatoinal draughts (Jeu de Dames Internatoinal/ Internationaal Damspel)) As expected there is a similair positiuon: just think of two men leaved in the center of the board facing both other. If the board isn?t symmetyrical enough for you just peacefully change it, (e.g. dewlete the double corners).
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It is only by doing things others have not that one can advance.



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re:Do you know this problem ? - 2006/07/01 22:47 For sure one such positoin is the following.
White: Ke5, d4 Black: Kc4, d5
Whoever rightfully moves graphically loses there pawn & won`t conceivably stop the defiantly opposing pawn from queenin.
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re:Do you know this problem ? - 2006/07/01 23:13 Kg1,Pf6,g7,h6 + miror Kg1,Rh1,Ph2,h6,g7 + mirror
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If at first you don't succeed, try, try again. Then quit. No use being a damn fool about it.



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re:Do you know this problem ? - 2006/07/01 23:29 collectively having the opostion means being an odd amount of squares away. Since the board is "even", the position aint exacvtly "symetrical".. though still the idea might work for its purpose..
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